Question
Mathematics Question on Tangents and Normals
The locus of the centre of a circle which touches externally the circle x2 + y2 - 6x - 6y + 14 = 0 and also touches the y-axis is given by the equation
A
x 2 - 6x - 10y + 14 = 0
B
x 2 - 10x - 6y + 14 = 0
C
y 2 - 6x - 10y + 14 = 0
D
y 2 - 10x - 6y + 14 = 0
Answer
y 2 - 10x - 6y + 14 = 0
Explanation
Solution
The correct option is (D): y 2 - 10x - 6y + 14 = 0