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Question: The locus of the centre of a circle which always passes through the fixed points (a, 0) and \(( - a ...

The locus of the centre of a circle which always passes through the fixed points (a, 0) and (a,0)( - a , 0 ), is.

A

x=1x = 1

B

x+y=6x + y = 6

C

x+y=2ax + y = 2 a

D

x=0x = 0

Answer

x=0x = 0

Explanation

Solution

Perpendicular bisector of join of the two points

(a,0)( a , 0 ) and (a,0)( - a , 0 ) i.e., x=0x = 0 .