Question

The locus of point of intersection of the lines $\sqrt{3}$x– y – 4$\sqrt{3}$k = 0 and $\sqrt{3}$kx + ky – 4$\sqrt{3}$= 0 represent a hyperbola then its eccentricity equals –

• A. $\sqrt{2}$
• B. 2
• C. $\sqrt{7}$
• D. $\sqrt{5}$

Answer 1

Answer: (B)

2

Answer 2

$\frac{\sqrt{3}x - y}{4\sqrt{3}}$= $\frac{4\sqrt{3}}{\sqrt{3}x + y}$

Ю 3x² – y² = 48

Ю $\frac{x^{2}}{16}$– $\frac{y^{2}}{48}$= 1

48 = 16 (e² –1) Ю e² = 4

Ю e = 2