Question

The locus of P such that area of $\Delta PAB = 12sq.$ units, where $A(2,3)$ and $B( - 4,5)$ is.

• A. $(x + 3y - 1)(x + 3y - 23) = 0$
• B. $(x + 3y + 1)(x + 3y - 23) = 0$
• C. $(3x + y - 1)(3x + y - 23) = 0$
• D. $(3x + y + 1)(3x + y + 23) = 0$

Answer 1

Answer: (B)

$(x + 3y + 1)(x + 3y - 23) = 0$

Answer 2

Let P be (x, y). $\Delta = \pm 12$

$\Rightarrow x + 3 y + 1 = 0$ and $x + 3 y - 23 = 0$.