Question

The locus of a point which moves so that it is always equidistant from the point A(a, 0) and B (– a, 0) is.

• A. A circle
• B. Perpendicular bisector of the line segment AB
• C. A line parallel to x-axis
• D. None of these

Answer 1

Answer: (B)

Perpendicular bisector of the line segment AB

Answer 2

Let point be (h, k) then,

$( h - a ) ^ { 2 } + k ^ { 2 } = ( h + a ) ^ { 2 } + k ^ { 2 }$

$\Rightarrow 4 h a = 0 \Rightarrow h = 0$ Hence x = 0.