Question

The lines of force of the electric field due to two charges q and Q are sketched in the figure. State if

• A. Q is positive and $\left| \left. \ Q \right| \right.\ > \left| \left. \ q \right| \right.\$
• B. Q is negative and $\left| \left. \ Q \right| \right.\ > \left| \left. \ q \right| \right.\$
• C. q is positive and $\left| \left. \ Q \right| \right.\ < \left| \left. \ q \right| \right.\$
• D. q is negative and $\left| \left. \ Q \right| \right.\ < \left| \left. \ q \right| \right.\$

Answer 1

Answer: (C)

q is positive and $\left| \left. \ Q \right| \right.\ < \left| \left. \ q \right| \right.\$

Answer 2

q is +ve because lines of force emerge from it and $\left| \left. \ Q \right| \right.\ < \left| \left. \ q \right| \right.\$ because more lines emerge from q and less lines terminate at Q.