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Question: The lines 2x – 3y = 5 and 3x – 4y = 7 are diameters of a circle of area 154 sq. units. Then the equa...

The lines 2x – 3y = 5 and 3x – 4y = 7 are diameters of a circle of area 154 sq. units. Then the equation of this circle is –

A

x2 + y2 + 2x – 2y = 62

B

x2 + y2 + 2x – 2y = 47

C

x2 +y2 – 2x + 2y = 47

D

x2 + y2– 2x + 2y = 62

Answer

x2 +y2 – 2x + 2y = 47

Explanation

Solution

2x – 3y = 5

3x – 4y = 7

Solving x = 1 y = 1

Centre (1, –1)

pr2 = 154

Ž r = 7

Equation (x – 1)2 + (y + 1)2 = 49