Question
Question: The lines 2x – 3y = 5 and 3x – 4y = 7 are diameters of a circle of area 154 sq. units. Then the equa...
The lines 2x – 3y = 5 and 3x – 4y = 7 are diameters of a circle of area 154 sq. units. Then the equation of this circle is –
A
x2 + y2 + 2x – 2y = 62
B
x2 + y2 + 2x – 2y = 47
C
x2 +y2 – 2x + 2y = 47
D
x2 + y2– 2x + 2y = 62
Answer
x2 +y2 – 2x + 2y = 47
Explanation
Solution
2x – 3y = 5
3x – 4y = 7
Solving x = 1 y = 1
Centre (1, –1)
pr2 = 154
Ž r = 7
Equation (x – 1)2 + (y + 1)2 = 49