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Question

Question: The line\(\frac{x - 2}{3} = \frac{y - 3}{4} = \frac{z - 4}{5}\)is parallel to the plane...

The linex23=y34=z45\frac{x - 2}{3} = \frac{y - 3}{4} = \frac{z - 4}{5}is parallel to the plane

A

3x+4y+5z=73x + 4y + 5z = 7

B

2x+y2z=02x + y - 2z = 0

C

x+yz=2x + y - z = 2

D

2x+3y+4z=02x + 3y + 4z = 0

Answer

2x+y2z=02x + y - 2z = 0

Explanation

Solution

Trick: Since line is parallel to plane if al+bm+cn=0a l + b m + c n = 0

\therefore From option (2), 3(2)+4(1)+5(2)=03 ( 2 ) + 4 ( 1 ) + 5 ( - 2 ) = 0.

Clearly, 2x+y2z=02 x + y - 2 z = 0 is the required plane.