Question
Question: The linear mass density of a ladder of length \(l\) increases uniformly from one end \(A\) to the ot...
The linear mass density of a ladder of length l increases uniformly from one end A to the other end B ,
(i) Form an expression for linear mass density as a function of distance x from end A where linear mass density λ0 . The density at one end being twice that of the other end.
(ii) Find the position of the center of mass from end A .
Solution
Use the formula of the linear mass density and find it at the point A itself by substituting the distance and the density to obtain the expression. Then substitute the obtained expression in the value of the distance of the center of mass to obtain the answer.
Formula used:
The formula of the linear mass density is given by
λ=Ax+B
Where λ is the linear mass density and AandB are the two ends of the ladder.
Complete step by step solution:
It is given that the
Length of the ladder is l
The linear mass density is λ0
At the point A , the distance between the points is zero and the linear mass density λ=λ0. And at point B , at a distance x from the point A , The density at one end is twice the other end, hence λ=2λ0 .
From these boundary points, we get A=lλ0 and the value of the B=λ0 . Substituting these in the formula of the linear mass density,
λ=Ax+B
λ=lλ0x+λ0
It is known that the
X=∫01dm∫01xdm and the dm=λdx
Substitute the value of the λ in the dm formula,
Hence the dm obtained is lλ0x+λ0 .
Substituting the value of the dm in the formula of X .
X=∫01(lλ0x+λ0)dx∫01x(lλ0x+λ0)dx
By simplifying the above step, we get
X=951
Hence the centre of mass is at a distance of 951cm from the point A .
Note: The integration is done to find the distance of the center of the mass from the given point. Remember the integration formula of the distance and also the linear mass density. The linear mass density is the mass per unit length.