Question: The line $x + y = 2$ is tangent to the curve $x^{2} = 3 - 2y$ at its point...

Question

The line $x + y = 2$ is tangent to the curve $x^{2} = 3 - 2y$ at its point

Answer 1

Given curve $x^{2} = 3 - 2y$

diff. w.r.t. x, $2x = - \frac{2dy}{dx}$ ; $\frac{dy}{dx} = - x$

Slope of the line = – 1

$\frac{dy}{dx} = - x = - 1$ ; $x = 1$

$\therefore y = 1$ point (1, 1)

Question: The line \(x + y = 2\) is tangent to the curve \(x^{2} = 3 - 2y\) at its point...