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Question: The line \[x - 7 = 0\] is A.Parallel to \[y\]-axis. B.Parallel to \[x\]-axis. C.Passing throug...

The line x7=0x - 7 = 0 is
A.Parallel to yy-axis.
B.Parallel to xx-axis.
C.Passing through the origin.
D.None of these.

Explanation

Solution

We will first solve the given equation to find the value of xx. We will then form a table to find the value of xx with respect to yy. We will then draw a graph using the table to find the nature of the line whether it is parallel to xx-axis, yy-axis or passing through the origin.

Complete step by step solution:
We will first solve the given equation to find the value of xx. We will then form a table to find the value of xx with respect to yy. We will then draw a graph using the table to find the nature of the line whether it is parallel to xx-axis, yy-axis or passing through the origin.

xx777777
yy2 - 21 - 10123

Hence, from this table it is proved that for any value of yy (both negative and positive), xx will always hold the same value.
Hence, the graph of the line x7=0x - 7 = 0 will be:

From this graph, we can say that it holds a constant value of x=7x = 7 and it is parallel to yy-axis.

Hence, option A is the correct option.

Note: Since, the line is parallel to yy-axis, clearly, it should be perpendicular to xx-axis. Also, from the graph, the line makes a right angle with xx-axis hence, it is perpendicular to it. The equation of a straight line parallel to yy-axis at a distance ‘aa’ from it is x=ax = a.
Also, the equation of a straight line parallel to xx-axis at a distance ‘b’ from it is y=by = b. The equation of yy-axis is x=0x = 0 , because yy-axis is parallel to itself at a distance 0 from it. Similarly, the equation of xx-axis is y=0y = 0 , because xx-axis is parallel to itself at a distance 0 from it.