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Question: The line through point ( m , -9 ) and ( 7 , m ) has slope m. The y – intercept of this line is A)...

The line through point ( m , -9 ) and ( 7 , m ) has slope m. The y – intercept of this line is
A) -18
B) -6
C) 6
D) 18

Explanation

Solution

Hint: First find the slope of the line using the points through which it passes and equating it to m. On further solving the quadratic equation the value of m could be found. Find the equation of the line and put x = 0 to get the y intercept.

Complete step-by-step answer:
Let us find the slope of the given line ,
= (y2y1x2x1)\left( {\dfrac{{y_2 - y_1}}{{x_2 - x_1}}} \right)
= (m(9)7m)\left( {\dfrac{{m - \left( { - 9} \right)}}{{7 - m}}} \right)
= m+97m\dfrac{{m + 9}}{{7 - m}}
But it is given that the slope is m .
Therefore,
m+97m\dfrac{{m + 9}}{{7 - m}} = m
\Rightarrow m+9=m(7m)m + 9 = m\left( {7 - m} \right)
m+9=7mm2\Rightarrow m + 9 = 7m - {m^2}
m26m9=0\Rightarrow {m^2} - 6m - 9 = 0
(m3)2=0\Rightarrow {\left( {m - 3} \right)^2} = 0
m=3\Rightarrow m = 3
Now the equation of the line \to
yy1=m(xx1)y - y_1 = m\left( {x -x_1} \right)
\Rightarrow y(9)=m(xm)y - \left( { - 9} \right) = m\left( {x - m} \right)
Putting m = 3
\Rightarrow y+9=3(x3)y + 9 = 3\left( {x - 3} \right)
For finding the y intercept we have to put x = 0 in the above equation .
\Rightarrow y+9=3(03)y + 9 = 3\left( {0 - 3} \right)
y+9=9\Rightarrow y + 9 = - 9
y=18\Rightarrow y = - 18
Therefore, -18 is the required y intercept.

Note: In such questions we should know the concept and formula of slope intercept from a point to get the desired answer. Remember that on putting x=0, we get the y intercept and on putting y=0, we get the x intercept.