Solveeit Logo
Login

Question

Mathematics Question on Three Dimensional Geometry

The line, that is coplanar to the line x+3−3=y−11=z−55\frac{x+3}{-3}=\frac{y-1}{1}=\frac{z-5}{5} is

A

x−1−1=y−22=z−55\frac{x-1}{-1}=\frac{y-2}{2}=\frac{z-5}{5}

B

x+1−1=y−22=z−55\frac{x+1}{-1}=\frac{y-2}{2}=\frac{z-5}{5}

C

x+1−1=y−22=z−54\frac{x+1}{-1}=\frac{y-2}{2}=\frac{z-5}{4}

D

x+11=y−22=z−55\frac{x+1}{1}=\frac{y-2}{2}=\frac{z-5}{5}

Answer

x+1−1=y−22=z−55\frac{x+1}{-1}=\frac{y-2}{2}=\frac{z-5}{5}

Explanation

Solution

The correct answer is (B) : x+1−1=y−22=z−55\frac{x+1}{-1}=\frac{y-2}{2}=\frac{z-5}{5}