Question
Question: The line segment joining (2, -3) and (5, 6) is divided by x-axis in the ratio: a. 2:1 b. 3:1 c...
The line segment joining (2, -3) and (5, 6) is divided by x-axis in the ratio:
a. 2:1
b. 3:1
c. 1:2
d. 1:3
Solution
We know that if any line segment joining to points let say A and B are divided by any other point C in a certain amount of ratio. Then the coordinates of C are given by the formula namely section formula, which is, (x,y) = (m + nmc + na,m + nmd + nb), where (x,y) is coordinates of C, (a,b) and (c,d) are the coordinates of A and B.
Using section formula, on simplifying we’ll get the equation to simplify for the ratio in which the x-axis divides the line segment, so the coordinate of any point on the x-axis is (a,0). Using this we can find the required ratio.
Complete step by step Answer:
Given: x-axis divides the line segment joining (2, -3) and (5, 6)
Let the point where this line segment divides the x-axis be, (a, 0), and also let the x-axis divide this line segment in the ratio m: n as all the ordinate of the points in the x-axis is zero.
Now we know, if a line joining (a,b)and (c,d) gets divided by a point (x,y) in the ratio m:n,
Then using section formula we can find the coordinates(x,y)
i.e. (x,y) = (m + nmc + na,m + nmd + nb)
now according to the given data, we have the points as(a,b) = (2, - 3) , and (c,d) = (5,6)
So on substituting the above values we get,
(a,0) = (m + nm×5 + n×2,m + nm6 + n( - 3))
Now on equating the y components, we get,
m + nm(6) + n( - 3)=0
Multiplying both sides by (m+n)
⇒6m - 3n = 0
⇒6m = 3n
Dividing both sides by 3
⇒2m = n
Now to get the value of ratio dividing both sides by n
∴nm = 21
Hence the correct option is C.
Note: We use section formula to find the coordinates of a point which divides the line joining two points in a ratio, internally or externally. If the value of the ratio is negative then the point is external, whereas if the value of the ratio is positive then the point is internal.