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Question: The line segment joining (2, -3) and (5, 6) is divided by x-axis in the ratio: a. 2:1 b. 3:1 c...

The line segment joining (2, -3) and (5, 6) is divided by x-axis in the ratio:
a. 2:1
b. 3:1
c. 1:2
d. 1:3

Explanation

Solution

We know that if any line segment joining to points let say A and B are divided by any other point C in a certain amount of ratio. Then the coordinates of C are given by the formula namely section formula, which is, (x,y) = (mc + nam + n,md + nbm + n){\text{(x,y) = (}}\dfrac{{{\text{mc + na}}}}{{{\text{m + n}}}}{\text{,}}\dfrac{{{\text{md + nb}}}}{{{\text{m + n}}}}{\text{)}}, where (x,y) is coordinates of C, (a,b) and (c,d) are the coordinates of A and B.
Using section formula, on simplifying we’ll get the equation to simplify for the ratio in which the x-axis divides the line segment, so the coordinate of any point on the x-axis is (a,0). Using this we can find the required ratio.

Complete step by step Answer:

Given: x-axis divides the line segment joining (2, -3) and (5, 6)
Let the point where this line segment divides the x-axis be, (a, 0), and also let the x-axis divide this line segment in the ratio m: n as all the ordinate of the points in the x-axis is zero.
Now we know, if a line joining (a,b){\text{(a,b)}}and (c,d){\text{(c,d)}} gets divided by a point (x,y){\text{(x,y)}} in the ratio m:n{\text{m:n}},
Then using section formula we can find the coordinates(x,y)
i.e. (x,y) = (mc + nam + n,md + nbm + n){\text{(x,y) = (}}\dfrac{{{\text{mc + na}}}}{{{\text{m + n}}}}{\text{,}}\dfrac{{{\text{md + nb}}}}{{{\text{m + n}}}}{\text{)}}
now according to the given data, we have the points as(a,b) = (2, - 3){\text{(a,b) = (2, - 3)}} , and (c,d) = (5,6){\text{(c,d) = (5,6)}}
So on substituting the above values we get,
(a,0) = (m×5 + n×2m + n,m6 + n( - 3)m + n){\text{(a,0) = (}}\dfrac{{{\text{m}} \times {\text{5 + n}} \times {\text{2}}}}{{{\text{m + n}}}}{\text{,}}\dfrac{{{\text{m6 + n( - 3)}}}}{{{\text{m + n}}}}{\text{)}}
Now on equating the y components, we get,
m(6) + n( - 3)m + n=0\dfrac{{{\text{m(6) + n( - 3)}}}}{{{\text{m + n}}}} = 0
Multiplying both sides by (m+n)
6m - 3n = 0\Rightarrow {\text{6m - 3n = 0}}
6m = 3n\Rightarrow {\text{6m = 3n}}
Dividing both sides by 3
2m = n\Rightarrow 2{\text{m = n}}
Now to get the value of ratio dividing both sides by n
mn = 12\therefore \dfrac{{\text{m}}}{{\text{n}}}{\text{ = }}\dfrac{{\text{1}}}{{\text{2}}}
Hence the correct option is C.

Note: We use section formula to find the coordinates of a point which divides the line joining two points in a ratio, internally or externally. If the value of the ratio is negative then the point is external, whereas if the value of the ratio is positive then the point is internal.