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Question

Mathematics Question on Conic sections

The line passing through the extremity A of the major axis and extremity B of the minor axis of the ellipse x2+9y2=9x^2 + 9y^2 = 9 meets its auxiliary circle a t the point M. Then, the area (insqunits) of the triangle with vertices at A, M and the origin O is

A

3110\frac{31}{10}

B

2910\frac{29}{10}

C

2110\frac{21}{10}

D

2710\frac{27}{10}

Answer

2710\frac{27}{10}

Explanation

Solution

The correct option is(D): 2710\frac{27}{10}

Equation of auxiliary circle is
x2+y2=9x^2 + y^2 =9
Equation of AM is x3+y1=1\frac{x}{3} +\frac{y}{1} = 1
on solving Eq s (i) and (ii) , we get M(125,95).M \bigg( -\frac{12}{5} , \frac{9}{5} \bigg) .

Now, area of A AOM = 12.OA×MN=2710squnits\frac{1}{2} .OA \times MN = \frac{27}{10} sq units