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Question: The line \(x - 1 = 0\)is the directrix of the parabola \(y ^ { 2 } - k x + 8 = 0\). Then one of the ...

The line x1=0x - 1 = 0is the directrix of the parabola y2kx+8=0y ^ { 2 } - k x + 8 = 0. Then one of the values of k is

A

18\frac { 1 } { 8 }

B

8

C

4

D

14\frac { 1 } { 4 }

Answer

4

Explanation

Solution

The parabola is y2=4k4(x8k)y ^ { 2 } = 4 \frac { k } { 4 } \left( x - \frac { 8 } { k } \right).

Putting . The equation is Y2=4k4XY ^ { 2 } = 4 \cdot \frac { k } { 4 } \cdot X

∴ The directrix is X+k4=0X + \frac { k } { 4 } = 0 i.e.,x1=0x - 1 = 0is the directrix. So 8kk4=1\frac { 8 } { k } - \frac { k } { 4 } = 1 \Rightarrow k=8,4k = - 8,4