The line 4x+6y+9=0 touches y2=4x at the pointegral | Mathematics | SolveeIt | Solveeit

Today, August 24

Question

The line 4x+6y+9=0 touches y2=4x at the point

A

$(-3,\frac{9}{4})$

B

$(-3,-\frac{9}{4})$

C

$(\frac{9}{4},-3)$

D

$(-\frac{9}{4},-3)$

Answer

$(\frac{9}{4},-3)$

Explanation

Solution

The correct option is (C): $(\frac{9}{4},-3)$