The line (3x – y + 5) + l (2x – 3y – 4) = 0 will be parallel... | MATH - DISTANCE BETWEEN TWO LINES, PERPENDICULAR | SolveeIt | Solveeit

Today, August 18

Question

The line (3x – y + 5) + l (2x – 3y – 4) = 0 will be parallel to y-axis, if l =

A

$\frac { 1 } { 3 }$

B

$\frac { - 1 } { 3 }$

C

$\frac { 3 } { 2 }$

D

$\frac { - 3 } { 2 }$

Answer

$\frac { - 1 } { 3 }$

Explanation

Solution

Slope of given line = $\frac { 1 } { 0 }$

Ž – 1 – 3 l = 0 $\left( \because \frac { 1 } { \infty } \rightarrow 0 \right)$

Ž l = $\frac { - 1 } { 3 }$