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Question: The line 3x – 4y + 7 = 0 is rotated through an angle \(\frac { \pi } { 4 }\) in the clockwise direct...

The line 3x – 4y + 7 = 0 is rotated through an angle π4\frac { \pi } { 4 } in the clockwise direction about the point (–1, 1). The equation of the line in its new position is-

A

7y + x – 6 = 0

B

7y – x – 6 = 0

C

7y + x + 6 = 0

D

7y – x + 6 = 0

Answer

7y + x – 6 = 0

Explanation

Solution

1)

Sol. As (–1, 1) is a point on 3x – 4y + 7 = 0, the rotation is possible.

Slope of the given line = 34\frac { 3 } { 4 }.

Slope of the line in its new position = 3411+34\frac { \frac { 3 } { 4 } - 1 } { 1 + \frac { 3 } { 4 } }= – 17\frac { 1 } { 7 }

The required equation is y – 1 = – 17\frac { 1 } { 7 } (x + 1)

or 7y + x – 6 = 0.