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Question

Chemistry Question on Electrochemistry

The limiting molar conductivities of NaINaI, NaNO3NaNO_3 and AgNO3AgNO_3 are 12.712.7, 12.012.0 and 13.313.3 mS m2 mol–1, respectively (all at 25°C). The limiting molar conductivity of AgIAgI at this temperature is ____ mS m2 mol–1.

Answer

The limiting molar conductivity of AgIAgI,
Λm0(AgI)=Λm0(NaI)+Λm0(AgNO3)Λ0m(NaNO3)Λ^0_m(AgI) = Λ^0_m(NaI)+Λ^0_m(AgNO_3)-Λ^0m(NaNO_3)
Λm0(AgI)=12.7+13.312.0Λ^0_m(AgI) = 12.7 + 13.3 – 12.0
Λm0(AgI)=2612Λ^0_m(AgI) = 26 – 12
Λm0(AgI)=14 mSm2mol1Λ^0_m(AgI) =14\ mS m^2 mol^{–1}

So, the answer is 14 mSm2mol114\ mS m^2 mol^{–1}.