Solveeit Logo
Login

Question

Physics Question on Pressure

The level of water in a tank is 5m high. A hole of area 1 cm21\,cm^2 is made at the bottom of the tank. The rate of leakage of water from the hole in m3/sm^3/s is (g=10 ms−2)(g=10\,ms^{-2})

A

10−310^{-3}

B

10−410^{-4}

C

10

D

10−210^{-2}

Answer

10−310^{-3}

Explanation

Solution

Velocity of water from the hole =2×5×10=10 m/s=\sqrt {2} \times 5 \times 10 = 10\, m / s So, Q=AV=1×10−4m2×10m/sQ = AV =1 \times 10^{-4} m ^{2} \times 10 m / s = 10−3m3/s10^{-3} m ^{3} / s