Question
Question: The length of the wire increases by 8 mm when a weight of 5 kg is hung. If all the conditions are th...
The length of the wire increases by 8 mm when a weight of 5 kg is hung. If all the conditions are the same but the radius of the wire is doubled, what will be the increase in its length?
(A) 2 mm
(B) 1 mm
(C) 0.5 mm
(D) 1.5 mm
Solution
For solid matter operating in the elastic region, the force on a component depends on its Young’s modulus. A change in the dimensions of the component is bound to change other parameters, too.
Formula used: F=YAlΔl, where F is the force on the component, A is the area of the cross section, l is the original length of the wire, Y is the Young’s modulus, and Δl is the change in the length of the wire due to the force applied.
Complete step by step answer:
In this question, we are provided with a wire on which force F is exerted in the form of a weight hung from it. We are required to find the change in length of the wire, when all the conditions remain the same except the cross section of the wire. The data given to us includes:
Change in length before Δl=8mm
Force on the wire F=5kg
We know that the Young’s modulus and the force on a wire depend as:
⇒F=YAlΔl
Bringing the unchanging parameters on the LHS according to the question:
⇒YFl=AΔl [Eq. 1]
We are told that the radius R of the wire is doubled. Thus, the area will change as:
⇒A′=πR′2=π(2R)2
⇒A′=4πR2=4A
As the LHS of Eq. 1 will remain constant, we can have the relation between the new and old dimensions as:
⇒AΔl=A′Δl′
To find the value of the new change in length:
⇒Δl′=A′AΔl
We put the known values in this equation to get:
⇒Δl′=4AA×8=48=2mm
Hence, the new change in length is given by option (A); 2 mm.
Note:
Young’s modulus of a material is defined as its ability to withstand the changes in length or cross section when under tension or compression. Since it is a material property, it is not constant. It also has different values in different directions.