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Question

Physics Question on simple harmonic motion

The length of the simple pendulum which ticks seconds is

A

0.5m0.5\,m

B

1m1\,m

C

1.5m1.5\,m

D

2m2\,m

Answer

1m1\,m

Explanation

Solution

The time period of a simple pendulum is T=2πLgT=2\pi \sqrt{\frac{L}{g}} where LL is length of the pendulum or L=gT24π2L=\frac{gT^{2}}{4\pi^{2}} (i)\ldots\left(i\right) The time period of the simple pendulum which ticks seconds is 2s2\, s T=2s\therefore T=2\, s Substituting in (i), we get L=(9.8ms2)(2s)24×(3.14)2=1mL=\frac{\left(9.8\,m\,s^{-2}\right)\left(2\,s\right)^{2}}{4\times\left(3.14\right)^{2}}=1\, m