Question

The length of the seconds pendulum on the surface of Earth is 1 m. Its length on the surface of Moon where g is $\frac { 1 } { 6 }$ th the value of g on the surface of Earth is –

• A. $\frac { 1 } { 6 }$ m
• B. 6 m
• C. $\frac { 1 } { 36 }$m
• D. 36 m

Answer 1

Answer: (A)

$\frac { 1 } { 6 }$ m

Answer 2

T = 2p ; T is constant l µ g.

If g is reduced by a factor of 6. Then l is reduced by a factor of 6.