Question

The length of the second's pendulum on the surface of Earth is 1m. Its length on the surface of Moon, where g is $\frac { 1 } { 6 }$th the value of g on the surface of Earth is –

• A. $\frac { 1 } { 6 }$m
• B. 6m
• C. $\frac { 1 } { 36 }$m
• D. 36m

Answer 1

Answer: (A)

$\frac { 1 } { 6 }$m

Answer 2

T = 2p $\sqrt { \frac { \ell } { \mathrm { g } } }$ ; T is constant. l µ g

If g is reduced by a factor of 6, then l is reduced by a factor of 6.