Question
Question: The length of the compound microscope is 14cm. The magnifying power for a relaxed eye is 25. If the ...
The length of the compound microscope is 14cm. The magnifying power for a relaxed eye is 25. If the focal length of the eye lens is 5cm, then the object distance for the objective lens will be:
(A)1.8cm(B)1.5cm(C)2.1cm(D)2.4cm
Solution
Since, it has been given that the eyes are relaxed it means the final image after refraction from the eye lens forms at infinity. This means the image formed by the objective lies at the focus of the eye lens. That is, the length of the microscope is equal to the sum of focal length of the eye lens and the distance at which the object is making the image.
Complete answer:
Let the distance of image from the pole of the objective lens be denoted by vo . Also, let the focus of the eye lens be denoted by fe . Then, we can write the length of the compound microscope (L) as:
⇒L=vo+fe
Here,