Question
Question: The length of sonometer wire AB is \(100cm\), where should the two bridges be placed from A to divid...
The length of sonometer wire AB is 100cm, where should the two bridges be placed from A to divide the wire in 3 segments whose fundamental frequencies are in the ratio of 1:2:6
A. 30cm,90cm
B. 60cm,90cm
C. 40cm,80cm
D. 20cm,30cm
Solution
Sonometer is basically used to study the relationship between frequency, tension, and linear mass density and length of a stretched string. A Sonometer is a device based on the principle of Resonance. It is used to verify the laws of vibration of stretched string and also to determine the frequency of a tuning fork.
Complete answer:
Given,
The length of sonometer wire, AB=100cm
Ratio of segments =1:2:6
Let L1,L2andL3be the lengths of three segments.
Then
L1+L2+L3=100 ……………...(1)
Also the laws of vibrations of stretched strings
f1L1=f2L2=f3L3
Given
⇒f1:f2:f3=1:2:6
Therefore
=L1:2L2:6L3
So
L2=2L1
L3=6L1
Put the value in equation (1) and we get
⇒L1+2L1+6L1=100
Simplify
⇒66L1+3L1+L1=100
⇒10L1=100×6
⇒L1=10600
⇒L1=60cm
Now
⇒L2=2L1
⇒L2=260
⇒L2=30cm
Again
⇒L3=6L1
⇒L3=660
⇒L3=10cm
Now
The first bridge, L1=60cm
The second bridge, L1+L2
=60+30
=90cm
The second bridge is, L1+L2=90cm
So the answer is (2) 60cm,90cm.
Additional Information:
The monochord was used as a musical teaching tool in the 11th century by Guido of Arezzo (c. 990-1050), the musician who invented the first useful form of musical notation.
Note: This is known as resonance - when one object vibrating at the same natural frequency of a second object forces that second object into vibrational motion. The word resonance comes from Latin and means to "respond" - to sound out together with a loud sound. Resonance describes the phenomenon of increased amplitude that occurs when the frequency of a periodically applied force (or a Fourier component of it) is equal or close to a natural frequency of the system on which it acts.