Question

The length of simple pendulum executing SHM is increased by 21%. The percentage increase in the time period of the pendulum is –

• A. 10%
• B. 11 %
• C. 21%
• D. 42 %

Answer 1

Answer: (A)

10%

Answer 2

$\frac{T'}{T}$ = $\sqrt{\frac{121}{100}}$ Ž T ¢ = $\frac{11}{10}$T

$\left( \frac{T'}{T} - 1 \right)$ × 100 % = $\left( \frac{11}{10} - 1 \right)$ × 100 % = 10%