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Question: The length of carbon-carbon single bond of the compounds ![](https://www.vedantu.com/question-sets...

The length of carbon-carbon single bond of the compounds

is expected to increase in the order
(A) Ⅲ > Ⅱ > Ⅰ > Ⅳ
(B)Ⅰ > Ⅲ > Ⅱ > Ⅳ
(C) Ⅲ > Ⅳ > Ⅰ > Ⅱ
(D)Ⅱ > Ⅳ > Ⅰ > Ⅲ

Explanation

Solution

The length of the carbon-carbon single bond depends upon the hybridization of the carbon atom. The hybridization of the carbon contains S and P characters. More will be the p percentage, more will be the length of the carbon-carbon single bond.

Complete step by step solution:
For comparing the length of the carbon-carbon single bond, we need to check the hybridization of the carbons bonded via single bonds in each option.
In spsp , 50%50\% S and 50%50\% P character is there.
In sp2s{p^2} , 33.33%33.33\% S and 66.66%66.66\% P character is there.
In sp3s{p^3} , 25%25\% S and 75%75\% P character is there.
Checking each option separately,
(Ⅰ)

C2{C_2} and C3{C_3} are sp2s{p^2} and spsp hybridized respectively.
(Ⅱ)

Both C2{C_2} and C3{C_3} are spsp hybridized respectively.
(Ⅲ)

C1{C_1} and C2{C_2} are sp3s{p^3} and sp2s{p^2} hybridized respectively.
(Ⅳ)
\because
Here, both C2{C_2} and C3{C_3} are sp2s{p^2} hybridized respectively.
Now, we know as the p character increases, the bond length of the carbon-carbon single bond increases.
Combining the percentage p character of the carbon-carbon single bond,
For the molecule in option (Ⅰ),
Total p percentage of carbons bonded via single bond = 66.66%+50%=116.66%66.66\% + 50\% = 116.66\%
( \because C2{C_2} and C3{C_3} are sp2s{p^2} and spsp hybridized respectively.)
For the molecule in option (Ⅱ),
Total p percentage of carbons bonded via single bond = 50%+50%=100%50\% + 50\% = 100\%
( \because C2{C_2} and C3{C_3} are spsp hybridized respectively.)
For the molecule in option (Ⅲ),
Total p percentage of carbons bonded via single bond = 75%+66.66%=141.66%75\% + 66.66\% = 141.66\%
( \because C1{C_1} and C2{C_2} are sp3s{p^3} and sp2s{p^2} hybridized respectively.)
For the molecule present in option (Ⅳ),
Total p percentage of carbons bonded via single bond = 66.66%+66.66%=133.32%66.66\% + 66.66\% = 133.32\%
( \because C2{C_2} and C3{C_3} are sp2s{p^2} hybridized respectively.)
Now, we can easily compare on the basis of combined percentage p character.
The molecule in option (Ⅲ) will have the longest carbon-carbon single bond length followed by (Ⅳ),
(Ⅰ) and (Ⅱ).
Therefore, the correct order will be Ⅲ > Ⅳ > Ⅰ > Ⅱ
So, the correct option will be option C: Ⅲ > Ⅳ > Ⅰ > Ⅱ.

Additional information:
A carbon-carbon bond is a covalent bond between two carbon atoms. Single bond is the most common form: a bond composed of two electrons, one from each of the two atoms. The carbon-carbon single bond is a sigma bond and is formed between one hybridized orbital from each of the carbon atoms.

Note:
The carbon-carbon single bond length is directly proportional to the combined percentage of p of both the carbon atoms bonded via single bond and inversely proportional to the combined percentage of s of both the carbon atoms bonded via single bond.
As the combined percentage of p increases, bond length of carbon-carbon single bond increases.