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Question: The length of a wire is l<sub>1</sub> when tension is T<sub>1</sub> and when tension is T<sub>2</sub...

The length of a wire is l1 when tension is T1 and when tension is T2. The natural length of the wire is

A

l1+l22\frac{l_{1} + l_{2}}{2}

B

l1l2\sqrt{l_{1}l_{2}}

C

l1T2l2T1T2T1\frac{l_{1}T_{2} - l_{2}T_{1}}{T_{2} - T_{1}}

D

l1T2+l2T1T2+T1\frac{l_{1}T_{2} + l_{2}T_{1}}{T_{2} + T_{1}}

Answer

l1T2l2T1T2T1\frac{l_{1}T_{2} - l_{2}T_{1}}{T_{2} - T_{1}}

Explanation

Solution

T1T2=l1ll2lor\frac{T_{1}}{T_{2}} = \frac{l_{1} - l}{l_{2} - l}or T1(l2 – l) = T2(l1 - l) or

l = l1T2l2T1T2T1\frac{l_{1}T_{2} - l_{2}T_{1}}{T_{2} - T_{1}}