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Question

Physics Question on Centre of mass

The length of a metal wire is l1, when the tension in it is T1, and is l2 when the tension is T2. The natural length of wire is

A

l1+l22\frac{l_1+l_2}{2}

B

l1l2\sqrt{l_1l_2}

C

l1T2l2T1T2T1\frac{l_1T_2-l_2T_1}{T_2-T_1}

D

l1T2+l2T1T2+T1\frac{l_1T_2+l_2T_1}{T_2+T_1}

Answer

l1T2l2T1T2T1\frac{l_1T_2-l_2T_1}{T_2-T_1}

Explanation

Solution

The correct option is (C) : l1T2l2T1T2T1\frac{l_1T_2-l_2T_1}{T_2-T_1}