Question
Question: The length of a focal chord of the parabola y2 = 4ax at a distance b from the vertex is c. Then...
The length of a focal chord of the parabola y2 = 4ax at a distance b from the vertex is c. Then
A
2a2 = bc
B
a3 = b2c
C
ac = b2
D
b2c = 4a3
Answer
b2c = 4a3
Explanation
Solution
Chord joining two points t1 and t2 is
(t1 + t2)y = 2x + 2at1t2
4+(t1+t2)22at1t2= b ... (1)
a (t1 – t2)2 = c ... (2)
By using (1) and (2), eliminate t1 & t2