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Question: The length of a focal chord of the parabola y2 = 4ax at a distance b from the vertex is c. Then...

The length of a focal chord of the parabola y2 = 4ax at a distance b from the vertex is c. Then

A

2a2 = bc

B

a3 = b2c

C

ac = b2

D

b2c = 4a3

Answer

b2c = 4a3

Explanation

Solution

Chord joining two points t1 and t2 is

(t1 + t2)y = 2x + 2at1t2

2at1t24+(t1+t2)2\left| \frac{2at_{1}t_{2}}{\sqrt{4 + (t_{1} + t_{2})^{2}}} \right|= b ... (1)

a (t1 – t2)2 = c ... (2)

By using (1) and (2), eliminate t1 & t2