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Question: The length of a cylinder is measured with a meter rod having least count 0.1 cm. Its diameter is mea...

The length of a cylinder is measured with a meter rod having least count 0.1 cm. Its diameter is measured with venier calipers having least count 0.01 cm. Given that length is 5.0 cm. and radius is 2.0 cm. The percentage error in the calculated value of the volume will be

A

1%

B

2%

C

3%

D

4%

Answer

3%

Explanation

Solution

Volume of cylinder V=πr2lV = \pi r^{2}l

Percentage error in volume

ΔVV×100=2Δrr×100+Δll×100\frac{\Delta V}{V} \times 100 = \frac{2\Delta r}{r} \times 100 + \frac{\Delta l}{l} \times 100

=(2×0.012.0×100+0.15.0×100)= \left( 2 \times \frac{0.01}{2.0} \times 100 + \frac{0.1}{5.0} \times 100 \right) =(1+2)%= (1 + 2)\% =3%3\%