Question

The length of a conductor having resistance 160 Ω, is compressed to 25% of its initial value. The new resistance will be

• A. 10 Ω
• B. 20 Ω
• C. 15 Ω
• D. 17 Ω

Answer 1

Answer: (A)

10 Ω

Answer 2

At constant volume, R ∝ $l^2$

R'=10 Ω