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Question

Physics Question on physical world

The length, breadth and thickness of a block are given by l=12cm,b=6cml=12\, cm , b=6 \,cm and t=2.45cm.t=2.45 \,cm . The volume of the block according to the idea of significant figures should be

A

1×102cm31 \times 10^{2} \,cm ^{3}

B

2×102cm32 \times 10^{2} \,cm ^{3}

C

1.763×102cm31.763 \times 10^{2} \,cm ^{3}

D

none of these

Answer

2×102cm32 \times 10^{2} \,cm ^{3}

Explanation

Solution

Using the relation for volume
VV = length × \times breadth ×\times thickness
=12×6×2.45=176.4=12 \times 6 \times 2.45=176.4
=1.764×102cm3=1.764 \times 10^{2} \,cm ^{3}
The minimum number of significant figures is 11 in thickness,
hence the volume will contain only one significant figure.
Therefore, V=2×102cm3V=2 \times 10^{2}\, cm ^{3}