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Question: The length and breadth are three rectangles are as given below, find area: 1.9 m and 6 m 2.17 m ...

The length and breadth are three rectangles are as given below, find area:
1.9 m and 6 m
2.17 m and 3 m
3.4 m and 14 m

Explanation

Solution

To find the required areas of the rectangles with given dimensions, consider the given dimensions as the lengths and breadths of the rectangles. Then we can use the formula of the area of a rectangle that is, length×breadth{\text{length}} \times {\text{breadth}}
which gives the required area of the rectangles with given lengths and breadths.

Complete step by step solution:
Find the area of the rectangles for the given dimensions by using the formula of the area of a rectangle that is, length×breadth{\text{length}} \times {\text{breadth}}
For the first given dimensions;
Consider that the length and breadth of the rectangle be 1.9 m and 6 m respectively.
Substitute 1.9 for length and 6 for breadth in the formula length×breadth{\text{length}} \times {\text{breadth}}
length×breadth=(1.9×6)m2 =11.4  m2  {\text{length}} \times {\text{breadth}} = \left( {1.9 \times 6} \right){{\text{m}}^2} \\\ = 11.4\;{{\text{m}}^{\text{2}}} \\\
Thus, the area of the rectangle with the given dimensions is 11.4  m211.4\;{{\text{m}}^2}.
For the second given dimensions;
Consider that the length and breadth of the rectangle are 2.17 m and 3 m respectively.
Substitute 1.9 for length and 6 for breadth in the formula length×breadth{\text{length}} \times {\text{breadth}}.
length×breadth=(2.17×3)m2 =6.51  m2  {\text{length}} \times {\text{breadth}} = \left( {2.17 \times 3} \right){{\text{m}}^2} \\\ = 6.51\;{{\text{m}}^{\text{2}}} \\\
Thus, the area of the rectangle with the given dimensions is 6.51  m26.51\;{{\text{m}}^2}.
For the third given dimensions;
Consider that the length and breadth of the rectangle are 3.4 m and 14 m respectively.
Substitute 3.4 for length and 14 for breadth in the formula length×breadth{\text{length}} \times {\text{breadth}}.
length×breadth=(3.4×14)m2 =47.6  m2  {\text{length}} \times {\text{breadth}} = \left( {3.4 \times 14} \right){{\text{m}}^2} \\\ = 47.6\;{{\text{m}}^{\text{2}}} \\\
Thus, the area of the rectangle with the given dimensions is 47.6  m247.6\;{{\text{m}}^2}.
Hence, the required areas of the rectangles formed by the given dimensions are 11.4  m211.4\;{{\text{m}}^2} , 6.51  m26.51\;{{\text{m}}^2} and 47.6  m247.6\;{{\text{m}}^2} respectively.

Note: In order to find the required area of the rectangles with given dimensions; we can also consider the lengths and breadths as 6 m and 1.9 m; 3 m and 2.17 m; 14 m and 3.4 m respectively. Then we can substitute the corresponding dimensions in the formula length×breadth{\text{length}} \times {\text{breadth}} to find the required areas of the rectangles formed by the given dimensions.