Question
Question: The law of a lifting machine is \( P = \dfrac{W}{{50}} + 1.5 \) . The velocity ratio of the machine ...
The law of a lifting machine is P=50W+1.5 . The velocity ratio of the machine is 100 . Find the maximum possible mechanical advantage and maximum possible efficiency of the machine
(A)50and50% (B)50and60% (C)60and60% (D)60and50%
Solution
Hint : In order to solve the question, we use the velocity ratio to obtain the maximum efficiency by dividing the velocity ratio and the maximum advantage .
We can obtain the maximum advantage by slope of the given law of the machine. Then percentage calculation can be done by percentage calculation.
ηmax=V.Rm.A×100% For the maximum efficiency of the machine and y=mx+c for the slope of the machine.
Complete Step By Step Answer:
Given,
We have the law of the lifting machine, P=50W+1.5
Now to find the maximum advantage of the machine we have to see the slope of the equation
So let, the slope of the machine equation is m .
So slope, m=501
W.A here is the inverse of the slope obtained so maximum advantage here for the machine is m1=50 .
Now to find the efficiency of the machine let η be the efficiency and η max be the maximum efficiency of the machine.
So according to the efficiency, ηmax=V.Rm.A×100%
Where m.A is the maximum advantage of the machine . V.R is the velocity ratio that is given.
So,
\eta_{\max} = \dfrac{{50}}{{100}} \times 100\% \\\
= 50\% \\\
Option A is correct.
Note :
To get the slope of the law equation of the machine, use y=mx+c where assume P and W as
y x
respectively.
To get the maximum efficiency of the machine use the efficiency formula and convert into percentage.
Maximum advantage is the inverse of the slope of the machine law equation.