The last element of the (p)-block in (6^{th}) period is repr... | Chemistry | SolveeIt

The last element of the $p$ -block in $6^{th}$ period is represented by the outer most electronic configuration

$7s^2 7p^6$

$5f^{14}6d^{10}7s^27p^5$

$4f^{14}5d^{10}6s^26p^4$

$4f^{14}5d^{10}6s^26p^6$

Answer

$4f^{14}5d^{10}6s^26p^6$

Explanation

The last element of the $p$ -block in $6^{th}$ period is Radon $(Rn)$

The electronic configuration of $Rn$ is $[ Xe ] 4 f ^{14} 5 d ^{10} 6 s ^{2} 6 p ^{6}$

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