Question

The last digit of number $7^{886}$ is

• A. 9
• B. 7
• C. 3
• D. 1

Answer 1

Answer: (A)

9

Answer 2

Since, $7^{1}=7$
$7^{2}=49,7^{3}=343,7^{4}=2401$
$\therefore 7^{886}=\left(7^{4}\right)^{221} 7^{2}$
$\therefore$ The last digit number $7^{886}$ is $9$