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Question

Mathematics Question on general and middle terms

The last digit in the integer 3101+1{{3}^{101}}+1 is

A

11

B

22

C

33

D

44

Answer

44

Explanation

Solution

The given integer is 3101+1.{{3}^{101}}+1.
Unit digit in 31=3{{3}^{1}}=3 in 32=9{{3}^{2}}=9 in 33=7{{3}^{3}}=7 in 34=1{{3}^{4}}=1 in 35=3{{3}^{5}}=3 [repeat]
Now, on dividing 101 by 4 we get remainder =1
\therefore Last digit in the integer 3101+1{{3}^{101}}+1
=31+1=4={{3}^{1}}+1=4