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Question: The largest positive term of H.P. whose first two terms are \(\frac{2}{5}\) and \(\frac{12}{23}\) is...

The largest positive term of H.P. whose first two terms are 25\frac{2}{5} and 1223\frac{12}{23} is

A

2

B

6

C

12

D

20

Answer

6

Explanation

Solution

A.P. is 52,2312\frac{5}{2},\frac{23}{12},……..

Tn = 52\frac{5}{2} + (n – 1) (23123012)\left( \frac{23}{12} - \frac{30}{12} \right)

Tn = 527(n1)12\frac{5}{2} - \frac{7(n - 1)}{12} > 0

Ž 30 > 7(n – 1)

Ž n – 1 < 307\frac{30}{7}

Ž n < 377\frac{37}{7}

so n = 5

so largest term

Tn = 527.412\frac{5}{2} - \frac{7.4}{12} = 5273\frac{5}{2} - \frac{7}{3} = 16\frac{1}{6}

for H.P. = 6