The Ksp for bismuth sulphide (Bi2S3) is 1.08 × 10–73. The so... | Chemistry | SolveeIt | Solveeit

Today, August 24

Question

The Ksp for bismuth sulphide (Bi2S3) is 1.08 × 10–73. The solubility of Bi2S3 in mol L–1 at 298 K is

A

1.0 × 10–15

B

2.7 × 10–12

C

3.2 × 10–10

D

4.2 × 10–8

Answer

1.0 × 10–15

Explanation

Solution

The correct option is(A): 1.0 × 10–15

$Bi_2S3⇋2Bi^3+2s+3s^2-3s$

Ksp = (2s)2(3s)3 = 108s5

108s5 = 108 × 10–75

s = 1.0 × 10–15 mol/L