Question

The Kohinoor diamond was the largest diamond ever found. How many moles of carbon atoms are present in it, if it weighs $3300$ carats? [Given: $1$ carat $= 200{\text{mg}}$ ]

Answer 1

This is a very easy question which can be solved by doing a simple conversion. To solve this question, we have to convert carats into milligram or later in grams. And then we will use simple application of the mole concept.

Complete Step-by-Step Solution
It is provided in the question that
$1$ carat $= 200{\text{mg}}$
And it is stated in the question that the Kohinoor diamond weighs $3300$ carats.
So, the weight of $3300$ carats will be equal to
$3300 \times 200 = 660000{\text{mg}}$
Now, we need to convert this milligrams value into grams
We know that $1000{\text{mg}} = 1{\text{gm}}$
Therefore, $660000{\text{mg}} = 660{\text{g}}$
So, we have found out the weight of Kohinoor diamond as $660{\text{gm}}$
Now, we need to find out the number of moles of carbon atoms present in it
To calculate the number of moles of carbon atoms, we know that,
12g carbon atoms constitute 1 mole units of carbon atoms
So, we need to find the number of moles in $660{\text{gm}}$ of carbon atoms
That is
Number of moles in Kohinoor diamond $= \dfrac{{660}}{{12}} = 55{\text{ moles}}$
Hence, the number of moles in Kohinoor diamond is 55 moles.

Note
A convenient method of expressing the quantity of a substance is the mole concept. It is possible to break down any measurement into two parts: the numerical magnitude and the units in which the magnitude is expressed. In the field of chemistry, a mole is defined as the amount of a substance that contains exactly $6.02214076 \times {10^{23}}$ 'elementary entities' of the given substance. The number $6.02214076 \times {10^{23}}$ is commonly referred to as the constant of Avogadro and is often denoted by the ' ${N_A}$ ' symbol. Atoms, molecules, and other particles can be the fundamental entities that can be represented in moles.