Question

The kinetic energy of two masses m₁ and m₂ are equal their ratio of linear momentum will be

• A. m₁/m₂
• B. m₂/m₁
• C. $\sqrt{m_{1}/m_{2}}$
• D. $\sqrt{m_{2}/m_{1}}$

Answer 1

Answer: (C)

$\sqrt{m_{1}/m_{2}}$

Answer 2

Relation between linear momentum (P), man (m) and kinetic energy (E)

$P = \sqrt{2mE}$ ⇒ $P \propto \sqrt{m}$ [as E is constant]

$\therefore\frac{P_{1}}{P_{2}} = \sqrt{\frac{m_{1}}{m_{2}}}$