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Question: The kinetic energy of N molecules of O2 is x joule at - 123<sup>0</sup>C. Another sample of O2 at 27...

The kinetic energy of N molecules of O2 is x joule at - 1230C. Another sample of O2 at 270C has a kinetic energy of 2x. The latter sample contains _______ molecules of O2.

A

N

B

N/2

C

2 N

D

3 N

Answer

N

Explanation

Solution

K.EO2=32×N32×R×15032×N32×R×300=x2xK.EO2=N×1N×2=12K.E_{O2} = \frac{\frac{3}{2} \times \frac{N}{32} \times R \times 150}{\frac{3}{2} \times \frac{N}{32} \times R \times 300} = \frac{x}{2x}K.E_{O2} = \frac{N \times 1}{N \times 2} = \frac{1}{2}