Question

The kinetic energy of an electron in the first orbit of H atom is 13.6 eV. The total energy of an electron in the second orbit of He⁺ is

• A. 13.6 eV
• B. 3.4 eV
• C. –13.6 eV
• D. –3.4 eV

Answer 1

Answer: (C)

–13.6 eV

Answer 2

E = – 13.6$\frac{z^{2}}{n^{2}}eV$