Solveeit Logo

Question

Physics Question on Kinetic Energy

The kinetic energy of a particle moving along a circle of radius RR is KK. The force acting on the particle is

A

KR\frac{K}{R}

B

2KR\frac{2K}{R}

C

K2R\frac{K}{2R}

D

KR2\frac{K}{R^2}

Answer

2KR\frac{2K}{R}

Explanation

Solution

Kinetic energy of a particle, K=12mv2...(i)K=\frac{1}{2}mv^{2}\quad...\left(i\right) where mm is the mass and vv be speed of the particle. Force acting on the particle is F=mv2RF = \frac{mv^{2}}{R} F=2KRF= \frac{2K}{R} (Using(i)(i))