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Question: The kinetic energy of a particle executing S.H.M. is 16 J when it is at its mean position. If the ma...

The kinetic energy of a particle executing S.H.M. is 16 J when it is at its mean position. If the mass of the particle is 0.32 kg, then what is the maximum velocity of the particle

A

5m/s5m/s

B

15m/s15m/s

C

10m/s10m/s

D

20m/s20m/s

Answer

10m/s10m/s

Explanation

Solution

Kinetic energy at mean position,

Kmax=12mvmax2.vmax=2KmaxmK_{\max} = \frac{1}{2}mv_{\max}^{2}. \Rightarrow v_{\max} = \sqrt{\frac{2K_{\max}}{m}}

=2×160.32=100= \sqrt{\frac{2 \times 16}{0.32}} = \sqrt{100} =10m/s.= 10m/s.