Solveeit Logo

Question

Physics Question on simple harmonic motion

The kinetic energy of a particle executing SHM is maximum, when its displacement is equal to

A

zero

B

amplitude/4

C

amplitude/2

D

amplitude.

Answer

zero

Explanation

Solution

Uk=12Mω2(A2x2)U_k = \frac{1}{2} M \omega^2(A^2 - x^2) So, UkU_k is maximum, when x = 0.