Question

The kinetic energy and potential energy of a particle executing S.H.M. will be equal, when displacement is (amplitude = a)

• A. $a/2$
• B. $a\sqrt{2}$
• C. $a/\sqrt{2}$
• D. $\frac{a\sqrt{2}}{3}$

Answer 1

Answer: (C)

$a/\sqrt{2}$

Answer 2

According to problem Kinetic energy = Potential energy

⇒ $\frac{1}{2}m\omega^{2}(a^{2} - y^{2}) = \frac{1}{2}m\omega^{2}y^{2}$

⇒ $a^{2} - y^{2} = y^{2}$ ∴ $y = a/\sqrt{2}$